A BRIEF CONCEPT OF INEQUALITY AND SHORT TRICKS ALSO:

Hello floks.now i going to share a short story or u can said it as trick also..

in mumbai..there have a community..and there two family leaving opposite each other..in between their house separate by a divider..

• 1st family member are >,>= 
  
  
  • say as above divider is- = (servant of two families)

• 2 nd family member are <, <=

family members of 1st was rival to 2nd family member and vice-versa.so they were not enter to each other house.

satellite picture same as         >          >=

                                          ----- = -----
                                           <          <=

----->but twist of the story, "=" was common servant of their home.(kuch type ka lok hya jo iska ghar jalanwali news uska rival k ghar me lagata hya,or uska ghar ka news opposite waalo k ghar me laga te hya) so he or she could go two house easily.

------>again a twist,1st house ">"gender is male and >= gender is female(ghar me economical dik hamra papa hi dek vaal karta hya..iska koi dusre meaning or ladies ego pe heart karne ka khoyaish nehi hya..jis ka mn jo chahe le lo.papa or mamma)so ">" > ">="

same to same at 2nd family

now a example-

statement: A>B>C<=D=F<J>K>=L

conclusion:1.J>=L

2.B>F

3.J>D

4.A>K

5.D>A

ANSWER WITH DESCRIPTION---->1.false.in between J and L there have two sign > and >= according to story ">" > ">=" so it contradict with conclusion.

2.false.according to story when we go forward B to F there >and<= present,who are rival to each other.so it not follow.

3.true.there have only two sign = and < so their have no problem each other.

4.false.because there have rival sign present..so it not follow.when we go forward A to k.

5.false.because when we go forward from D to A there >,>,<= sign present which show contradiction.

now a special type example:

statement:T>I>O<=K<L>E=F<W

conclusion:1.T>=k

2.L>W

3.K<T

4.w>L

5.I<T

ANSWER WITH EXPLANATION:1.FALSE.rival sign are present betweenT and K

2.FALSE.rival are present.

3.FALSE.rival sign are present between T and K.

4.FALSE.rival present.

5.TRUE.when we go forward from I to T we see T>I.so I<T.

------> but twist,between 1 are 3 either 1 follow or 3 follow.

trick:1.if subject and predicate are same.(in 1 and 3 T and K are same)

2.both conclusion should be wrong.

3.there sign have to present(>,<,=)

the conclusion obviously go for either or...

Thats all..a small trying to simply the inequality problem..study together rise together!!!!:)